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Answer the following Math Algebra question(F.1)

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Q1.(1+x)×4=x=? Q2.9k-1=-6k-31. k=? Q3.10-5x=1-x+1+2x.x=? Q4.0.4a-0.2(a-6)=0.5.a=? Q5.5[2(y-4.2)+y-1]=y-5.y=? 更新: Q1.(1+x)times4=?

最佳解答:

1. (1 + x) * 4 = 4 + 4x 2. 9k - 1 = - 6k - 31 9k = - 6k - 30 15k = -30 k = -2 3. 10 - 5x = 1 - x + 1 + 2x 10 - 5x = 2 + x -6x = - 8 x = 4 / 3 4. 0.4a - 0.2(a - 6) = 0.5 0.4a - 0.2a + 1.2 = 0.5 0.2a = - 0.7 2a = -7 a = - 7 / 2 5. 5[2(y-4.2)+y-1]=y-5 5[2y - 8.4 + y - 1] = y - 5 2006-10-30 16:40:48 補充: 5.5[2y - 8.4 y - 1] = y - 510y - 42 5y - 5 = y - 515y - 47 = y - 514y = 42y = 3

其他解答:

Q1. (1+x)×4=4+4x Q2. 9k-1=-6k-31. 9k+6k = -31+1 15k = -30 k = -2 Q3. 10-5x=1-x+1+2x 10-1-1 = 5x -x +2x 8 = 6x x = 4/3 Q4. 0.4a-0.2(a-6)=0.5 0.4a - 0.2a - 0.2(-6) = 0.5 0.2a+1.2 = 0.5 0.2a = -0.7 a = -3.5 Q5. 5[2(y-4.2)+y-1]=y-5 10y-42+y-1 = y-5 10y-43 = -5 10y = 38 y = 3.8 2006-10-30 16:32:05 補充: Q5.5[2(y-4.2) y-1]=y-510y-42 *5y-5* = y-515y-47 = y-514y = 42y = 3 2006-10-30 16:36:44 補充: Q5.10y-42*加5y-5 = y-5唔知點解個*加*號出唔到~~
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