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標題:
what's wrong????
發問:
the following work shows that for any two equal numbers a & b, we have 1=2. what is wrong in the work? a=b ab=b^2 ab-a^2=b^2-a^2 a(b-a)=(b+a)(b-a) a=b+a a=b+b a=2b b=2b 1=2
最佳解答:
a=b ab=b^2 ab-a^2=b^2-a^2 a(b-a)=(b+a)(b-a)
其他解答:
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