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The sulphuric acid obtained by contact process contains 98% by mass of sulphuric acid and has a density of 1.84 g cm-3. Calculate the volume of the acid required for dilution to 500cm3 of 0.10M sulphuric acid. 我知道first 計no. of moles of H2SO4 : 500/1000 X 0.1 = 0.05 molTHEN 應該點牙? 1.84 X 98% ?... 顯示更多 The sulphuric acid obtained by contact process contains 98% by mass of sulphuric acid and has a density of 1.84 g cm-3. Calculate the volume of the acid required for dilution to 500cm3 of 0.10M sulphuric acid. 我知道first 計no. of moles of H2SO4 : 500/1000 X 0.1 = 0.05 mol THEN 應該點牙? 1.84 X 98% ? <<< this process 岩唔岩牙? thenn... 唔識.. 請教我~ thx

最佳解答:

molar mass of H2SO4 is 1*2+32+16*4 = 98 g/mol The no of mole of H2SO4 cm-3 of result sulphuric acid is: 1.84 g cm-3 * 98% / ( 98 g/mol ) = 0.0184 mol cm-3 The no of mole of diluted sulphuric acid is 0.10 * 500/1000 = 0.05 mol (you given) Thus, the volume of the acid is: 0.05 mol / (0.0184 mol cm-3) = 2.717 cm3

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