問3題因式分解 @ ute40zf07t的部落格

標題:

問3題因式分解

發問:

(x + 1)2 + (x ? 1)2 + 2(x2 ? 1) (a2 + bc)2 ? (b + c)2a2 要步驟...thx 6(a + b)2 ? 2(a + b)

最佳解答:

1. (x+1)2+(x-1)2+2(x2-1) =2x+2+2x-2+4x-2 =8x-2 2. (a2+bc)2-(b+c)2a2 =4a+2bc-4ab-4ac =4a-4ab-2bc =2a(2-2b-c) 3.6(a+b)2-2(a+b) =12a+12b-2a-2b =10a+10b =10(a+b)

其他解答:

1)如果當 2(x2 ? 1)內的x是英文字母x的話,那便是: (x+1)2+(x-1)2+2(x2-1) =(2x+2)+(2x-2)+(4x-2) =(2x+2x+4x)+(2-2-2) =10x-2,, 但如果當 2(x2 ? 1) 的x是數學符號的話,那便是: (x+1)2+(x-1)2+2(x2-1) =(2x+2)+(2x-2)+2 =(2x+2x)+(2-2+2) =4x+2,, 2)(a2 + bc)2 ? (b + c)2a2 =(4a+2bc)-(4ab+4ac) =4a+2bc-4ab-4ac =-4ab-4ac+2bc+4a,, 3)6(a + b)2 ? 2(a + b) =(6a+6b)2-(2a+2b) =12a+12b-2a-2b =12a-2a+12b-2b =10a+10b,, **Hope I can help you!**|||||1. (x+1)2+(x-1)2+2(x2-1) =2x+2+2x-2+4x-2 =8x-2 2. (a2+bc)2-(b+c)2a2 =4a+2bc-4ab-4ac =4a-4ab-2bc =2a(2-2b-c) 3.6(a+b)2-2(a+b) =12a+12b-2a-2b =10a+10b =10(a+b)|||||1) (x + 1)(2) + (x - 1)(2) + (2)(x^2 - 1) =(x + 1)(2) + (x - 1)(2) + (2)(x - 1)(x + 1) =(2) [(x+1) + (x-1) + (x-1)(x+1)] 2) (a^2 + bc)(2) – (b + c)(2a^2) =(2) [(a^2 + bc) – (b + c)(a^2)] 3)6(a + b)(2) – 2(a + b) =[(2)(a + b)] [6-1] =[(2)(a + b)] (5) =10(a+b) 因為唔知你第一同第2題個2係咪解square而出既answer 如果係square, 可以再答你